What is the answer to 3^{2x}=9^{3x+1} ?

The answer to 3^{2x}=9^{3x+1} is x=-1/2

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3^{2x}=9^{3x+1}

3^{2 x} = 9^{3 x + 1}

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

3^{2 x} = 9^{3 x + 1}

Apply exponent rules

2 x = 2 (3 x + 1)

Solve

2 x = 2 (3 x + 1) : x = - \frac{1}{2}

x = - \frac{1}{2}

lo g_{5} (7^{3 x}) = 10

4^{- \frac{1}{x}} = \frac{1}{2}

5. 5^{r} = 1.6

2^{2 x} - 29 (2^{x}) - 96 = 0

8^{12 x} - 8^{6 x} - 56 = 0