What is the answer to 8^{12x}-8^{6x}-56=0 ?

The answer to 8^{12x}-8^{6x}-56=0 is x= 1/6

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8^{12x}-8^{6x}-56=0

8^{12 x} - 8^{6 x} - 56 = 0

x = \frac{1}{6}

Solution steps

8^{12 x} - 8^{6 x} - 56 = 0

Apply exponent rules

(8^{x})^{12} - (8^{x})^{6} - 56 = 0

Rewrite the equation with

8^{x} = u

(u)^{12} - (u)^{6} - 56 = 0

Solve

u^{12} - u^{6} - 56 = 0 : u = 2, u = - 2

u = 2, u = - 2

Substitute back

u = 8^{x},

solve for

x

Solve

8^{x} = 2 : x = \frac{1}{6}

Solve

8^{x} = - 2 :

No Solution for

x \in R

x = \frac{1}{6}

9^{1 - 2 x} = \frac{1}{2 7 ^{x - 4}}

5^{3 y} = 64

5 ln (4 - 3^{x}) = 6

y, - 2^{y} + 5 = 7 x

5^{2 x + 3} = 125

What is the answer to 8^{12x}-8^{6x}-56=0 ?
The answer to 8^{12x}-8^{6x}-56=0 is x= 1/6
Solve for x: 8^{12x}-8^{6x}-56=0
The solution is x= 1/6