What is the answer to 5ln(4-3^x)=6 ?

The answer to 5ln(4-3^x)=6 is x=(ln(-e^{6/5}+4))/(ln(3))

Solve for x: 5ln(4-3^x)=6

The solution is x=(ln(-e^{6/5}+4))/(ln(3))

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5 ln (4 - 3^{x}) = 6

x = \frac{ln ( - e ^{\frac{6}{5}} + 4 )}{ln ( 3 )}

Decimal Notation

x = - 0.35120 \dots

Solution steps

5 ln (4 - 3^{x}) = 6

Rewrite the equation with

3^{x} = u

5 ln (4 - u) = 6

Solve

5 ln (4 - u) = 6 : u = - e^{\frac{6}{5}} + 4

u = - e^{\frac{6}{5}} + 4

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = - e^{\frac{6}{5}} + 4 : x = \frac{ln ( - e ^{\frac{6}{5}} + 4 )}{ln ( 3 )}

x = \frac{ln ( - e ^{\frac{6}{5}} + 4 )}{ln ( 3 )}

y, - 2^{y} + 5 = 7 x

5^{2 x + 3} = 125

57 = 2 5^{x}

\frac{5 ^{x + 1} - 5 ^{x}}{4} = 25

\frac{2 ^{x}}{2 ^{3 x}} = 2^{2 x}

What is the answer to 5ln(4-3^x)=6 ?
The answer to 5ln(4-3^x)=6 is x=(ln(-e^{6/5}+4))/(ln(3))
Solve for x: 5ln(4-3^x)=6
The solution is x=(ln(-e^{6/5}+4))/(ln(3))