What is the answer to 3^x2^{3x}=4 ?

The answer to 3^x2^{3x}=4 is x= 2/(log_{2)(3)+3}

Solve for x: 3^x2^{3x}=4

The solution is x= 2/(log_{2)(3)+3}

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3^{x} 2^{3 x} = 4

x = \frac{2}{lo g _{2} ( 3 ) + 3}

Decimal Notation

x = 0.43620 \dots

Solution steps

3^{x} \cdot 2^{3 x} = 4

Apply exponent rules

lo g_{2} (3) x + 3 x = 2

Solve

lo g_{2} (3) x + 3 x = 2 : x = \frac{2}{lo g _{2} ( 3 ) + 3}

x = \frac{2}{lo g _{2} ( 3 ) + 3}

6^{x - 3} = 17

(\frac{1}{2})^{x} = \frac{1}{8}

3^{x + 1} = 3^{x} + 18

3^{5 x + 2} = 9^{x + 4}

\frac{1}{81} = 3^{x}

What is the answer to 3^x2^{3x}=4 ?
The answer to 3^x2^{3x}=4 is x= 2/(log_{2)(3)+3}
Solve for x: 3^x2^{3x}=4
The solution is x= 2/(log_{2)(3)+3}