What is the answer to 4^{2x-3}=7^x ?

The answer to 4^{2x-3}=7^x is x=(6ln(2))/(4ln(2)-ln(7))

Solve for x: 4^{2x-3}=7^x

The solution is x=(6ln(2))/(4ln(2)-ln(7))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4^{2 x - 3} = 7^{x}

x = \frac{6 ln ( 2 )}{4 ln ( 2 ) - ln ( 7 )}

Solution steps

4^{2 x - 3} = 7^{x}

Apply exponent rules

(2 x - 3) ln (4) = x ln (7)

Solve

(2 x - 3) ln (4) = x ln (7) : x = \frac{6 ln ( 2 )}{4 ln ( 2 ) - ln ( 7 )}

x = \frac{6 ln ( 2 )}{4 ln ( 2 ) - ln ( 7 )}

4^{2 x + 3} = 8^{x + 5}

8^{4 n - 2} = 4^{3 n + 3}

(x^{2} - 5) (e^{x} - 5) = 0

16 = 2^{x - 2}

2^{x + 1} - 2^{x - 1} - 8 = 0

What is the answer to 4^{2x-3}=7^x ?
The answer to 4^{2x-3}=7^x is x=(6ln(2))/(4ln(2)-ln(7))
Solve for x: 4^{2x-3}=7^x
The solution is x=(6ln(2))/(4ln(2)-ln(7))