What is the answer to (x^2-5)(e^x-5)=0 ?

The answer to (x^2-5)(e^x-5)=0 is x=sqrt(5),x=-sqrt(5),x=ln(5)

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(x^2-5)(e^x-5)=0

(x^{2} - 5) (e^{x} - 5) = 0

x = 5, x = - 5, x = ln (5)

Solution steps

(x^{2} - 5) (e^{x} - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x^{2} - 5 = 0 or e^{x} - 5 = 0

Solve

x^{2} - 5 = 0 : x = 5, x = - 5

Solve

e^{x} - 5 = 0 : x = ln (5)

x = 5, x = - 5, x = ln (5)

16 = 2^{x - 2}

2^{x + 1} - 2^{x - 1} - 8 = 0

3^{5 x - 2} = 6

4^{5 - 9 x} = \frac{1}{8 ^{x - 2}}

\frac{1}{2} = 4^{x}

What is the answer to (x^2-5)(e^x-5)=0 ?
The answer to (x^2-5)(e^x-5)=0 is x=sqrt(5),x=-sqrt(5),x=ln(5)