What is the answer to solvefor t,N=3500(2^t) ?

The answer to solvefor t,N=3500(2^t) is t=(ln(N/(3500)))/(ln(2))

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solvefor t,N=3500(2^t)

solve for

t, N = 3500 (2^{t})

t = \frac{ln ( \frac{N}{3500} )}{ln ( 2 )}

Solution steps

N = 3500 (2^{t})

Switch sides

3500 \cdot 2^{t} = N

Divide both sides by

3500

2^{t} = \frac{N}{3500}

Apply exponent rules

t ln (2) = ln (\frac{N}{3500})

Solve

t ln (2) = ln (\frac{N}{3500}) : t = \frac{ln ( \frac{N}{3500} )}{ln ( 2 )}

t = \frac{ln ( \frac{N}{3500} )}{ln ( 2 )}

7 + 15 e^{1 - 3 x} = 10

2^{(x + 2)} = 16

8^{2 x} = 3^{2 x - 1}

2 e^{3 x - 7} - 6 = 3

1 0^{x + 7} = 4^{2 x}

What is the answer to solvefor t,N=3500(2^t) ?
The answer to solvefor t,N=3500(2^t) is t=(ln(N/(3500)))/(ln(2))