What is the answer to 66*10^{4x}=81 ?

The answer to 66*10^{4x}=81 is x=(ln(27/22))/(4ln(10))

Solve for x: 66*10^{4x}=81

The solution is x=(ln(27/22))/(4ln(10))

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66 \cdot 1 0^{4 x} = 81

x = \frac{ln ( \frac{27}{22} )}{4 ln ( 10 )}

Solution steps

66 \cdot 1 0^{4 x} = 81

Divide both sides by

66

1 0^{4 x} = \frac{27}{22}

Apply exponent rules

4 x ln (10) = ln (\frac{27}{22})

Solve

4 x ln (10) = ln (\frac{27}{22}) : x = \frac{ln ( \frac{27}{22} )}{4 ln ( 10 )}

x = \frac{ln ( \frac{27}{22} )}{4 ln ( 10 )}

2^{4 x} = 2^{3 x - 3}

3^{2 x + 1} + 8 (3^{x}) - 3 = 0

e^{2 l n (b)} = 256

\frac{1025}{8 + e ^{4 x}} = 5

4^{x} = 9 (5^{x})

What is the answer to 66*10^{4x}=81 ?
The answer to 66*10^{4x}=81 is x=(ln(27/22))/(4ln(10))
Solve for x: 66*10^{4x}=81
The solution is x=(ln(27/22))/(4ln(10))