What is the answer to 2^{x+1}=3x ?

The answer to 2^{x+1}=3x is No Solution for x\in\mathbb{R}

Solve for x: 2^{x+1}=3x

The solution is No Solution for x\in\mathbb{R}

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2^{x + 1} = 3 x

No Solution for x \in R

Solution steps

2^{x + 1} = 3 x

Prepare

2^{x + 1} = 3 x

for Lambert form:

1 = 3 x e^{l n (2) (- x - 1)}

Rewrite the equation with

- x ln (2) = u

and

x = - \frac{u}{ln ( 2 )}

1 = 3 (- \frac{u}{ln ( 2 )}) e^{l n (2) (- (- \frac{u}{l n ( 2 )}) - 1)}

Simplify

1 = - \frac{3 e ^{u - l n (2)} u}{ln ( 2 )}

Rewrite

1 = - \frac{3 e ^{u - l n (2)} u}{ln ( 2 )}

in Lambert form:

e^{u} u = - \frac{2 ln ( 2 )}{3}

Solve

e^{u} u = - \frac{2 ln ( 2 )}{3} :

No Solution for

u \in R

No Solution for x \in R

10 x - e^{- x} = 0

8^{4 x - 3} = (\frac{1}{16})^{x + 1}

4 e^{- x} = 3 e^{x} + 4

1 0^{x} = (1 0^{- 14}) (1 0^{2})

6 (3^{2 x}) = 2^{x + 1}

What is the answer to 2^{x+1}=3x ?
The answer to 2^{x+1}=3x is No Solution for x\in\mathbb{R}
Solve for x: 2^{x+1}=3x
The solution is No Solution for x\in\mathbb{R}