What is the answer to 3^{2x+1}=5 ?

The answer to 3^{2x+1}=5 is x=(ln(5)-ln(3))/(2ln(3))

Solve for x: 3^{2x+1}=5

The solution is x=(ln(5)-ln(3))/(2ln(3))

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3^{2 x + 1} = 5

x = \frac{ln ( 5 ) - ln ( 3 )}{2 ln ( 3 )}

Decimal Notation

x = 0.23248 \dots

Solution steps

3^{2 x + 1} = 5

Apply exponent rules

(2 x + 1) ln (3) = ln (5)

Solve

(2 x + 1) ln (3) = ln (5) : x = \frac{ln ( 5 ) - ln ( 3 )}{2 ln ( 3 )}

x = \frac{ln ( 5 ) - ln ( 3 )}{2 ln ( 3 )}

x, 2^{x + y} = 8

97 \cdot 2^{2 x} = 69

3^{9 x} = 3^{7 x + 8}

2000 = 4000 e^{- 0.1 x}

2^{x} + \frac{1}{2 ^{x - 2}} = 5

What is the answer to 3^{2x+1}=5 ?
The answer to 3^{2x+1}=5 is x=(ln(5)-ln(3))/(2ln(3))
Solve for x: 3^{2x+1}=5
The solution is x=(ln(5)-ln(3))/(2ln(3))