What is the answer to 97*2^{2x}=69 ?

The answer to 97*2^{2x}=69 is x=(ln(69/97))/(2ln(2))

Solve for x: 97*2^{2x}=69

The solution is x=(ln(69/97))/(2ln(2))

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97 \cdot 2^{2 x} = 69

x = \frac{ln ( \frac{69}{97} )}{2 ln ( 2 )}

Decimal Notation

x = - 0.24569 \dots

Solution steps

97 \cdot 2^{2 x} = 69

Divide both sides by

97

2^{2 x} = \frac{69}{97}

Apply exponent rules

2 x ln (2) = ln (\frac{69}{97})

Solve

2 x ln (2) = ln (\frac{69}{97}) : x = \frac{ln ( \frac{69}{97} )}{2 ln ( 2 )}

x = \frac{ln ( \frac{69}{97} )}{2 ln ( 2 )}

3^{9 x} = 3^{7 x + 8}

2000 = 4000 e^{- 0.1 x}

2^{x} + \frac{1}{2 ^{x - 2}} = 5

14 \cdot 4^{x - 1} = 2 \cdot 7^{x - 1}

4^{x} - 2^{x} = 0

What is the answer to 97*2^{2x}=69 ?
The answer to 97*2^{2x}=69 is x=(ln(69/97))/(2ln(2))
Solve for x: 97*2^{2x}=69
The solution is x=(ln(69/97))/(2ln(2))