What is the answer to 3^{x^2}=7 ?

The answer to 3^{x^2}=7 is x=sqrt((ln(7))/(ln(3))),x=-sqrt((ln(7))/(ln(3)))

Solve for x: 3^{x^2}=7

The solution is x=sqrt((ln(7))/(ln(3))),x=-sqrt((ln(7))/(ln(3)))

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3^{x^{2}} = 7

x = \frac{ln ( 7 )}{ln ( 3 )}, x = - \frac{ln ( 7 )}{ln ( 3 )}

Solution steps

3^{x^{2}} = 7

Apply exponent rules

x^{2} ln (3) = ln (7)

Solve

x^{2} ln (3) = ln (7) : x = \frac{ln ( 7 )}{ln ( 3 )}, x = - \frac{ln ( 7 )}{ln ( 3 )}

x = \frac{ln ( 7 )}{ln ( 3 )}, x = - \frac{ln ( 7 )}{ln ( 3 )}

9 e^{x} = 107

2^{b} = 7

77 = 2 3^{x}

3^{2 x} + 2 \cdot 3^{x} + 1 = 0

x, F x + e^{- x} F_{y} = 0

What is the answer to 3^{x^2}=7 ?
The answer to 3^{x^2}=7 is x=sqrt((ln(7))/(ln(3))),x=-sqrt((ln(7))/(ln(3)))
Solve for x: 3^{x^2}=7
The solution is x=sqrt((ln(7))/(ln(3))),x=-sqrt((ln(7))/(ln(3)))