What is the answer to 5^{x+1}=2*3^{2x} ?

The answer to 5^{x+1}=2*3^{2x} is x=(ln(5)-ln(2))/(2ln(3)-ln(5))

Solve for x: 5^{x+1}=2*3^{2x}

The solution is x=(ln(5)-ln(2))/(2ln(3)-ln(5))

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5^{x + 1} = 2 \cdot 3^{2 x}

x = \frac{ln ( 5 ) - ln ( 2 )}{2 ln ( 3 ) - ln ( 5 )}

Solution steps

5^{x + 1} = 2 \cdot 3^{2 x}

Apply exponent rules

(x + 1) ln (5) = ln (2) + 2 x ln (3)

Solve

(x + 1) ln (5) = ln (2) + 2 x ln (3) : x = \frac{ln ( 5 ) - ln ( 2 )}{2 ln ( 3 ) - ln ( 5 )}

x = \frac{ln ( 5 ) - ln ( 2 )}{2 ln ( 3 ) - ln ( 5 )}

3^{x - 1} = 9

2^{x + 2} - 2^{x - 3} = 12

7^{3 - 2 x} = 7^{- x}

2^{x} - 2^{- x} = 5 - 5 \cdot 2^{- x}

3^{5 x} \cdot 9^{x^{2}} = 27

What is the answer to 5^{x+1}=2*3^{2x} ?
The answer to 5^{x+1}=2*3^{2x} is x=(ln(5)-ln(2))/(2ln(3)-ln(5))
Solve for x: 5^{x+1}=2*3^{2x}
The solution is x=(ln(5)-ln(2))/(2ln(3)-ln(5))