en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1=e^{(-1)/3 (1^3+3+3c)}

Solution

1 = e^{\frac{- 1}{3} (1^{3} + 3 + 3 c)}

Solution

c = - \frac{4}{3}

+1

Solution steps

1 = e^{\frac{- 1}{3} (1^{3} + 3 + 3 c)}

Apply exponent rules

ln (1) = \frac{- 1}{3} (1^{3} + 3 + 3 c)

Solve

ln (1) = \frac{- 1}{3} (1^{3} + 3 + 3 c) : c = - \frac{4}{3}

c = - \frac{4}{3}

Popular Examples

2^{x^2-14}= 1/1024

2^{x^{2} - 14} = \frac{1}{1024}

3^{2x-1}x^9=3^{x+2}x^{27}

3^{2 x - 1} x^{9} = 3^{x + 2} x^{27}

solvefor x,8^y=4^{2x+1}solve for

x, 8^{y} = 4^{2 x + 1}

e^{4x}+2e^{2x}-8=0

e^{4 x} + 2 e^{2 x} - 8 = 0

solvefor k,k(x)=x^4e^{3x}solve for

k, k (x) = x^{4} e^{3 x}

Frequently Asked Questions (FAQ)

What is the answer to 1=e^{(-1)/3 (1^3+3+3c)} ?
The answer to 1=e^{(-1)/3 (1^3+3+3c)} is c=-4/3