What is the answer to 71=21^x ?

The answer to 71=21^x is x=(ln(71))/(ln(21))

The solution is x=(ln(71))/(ln(21))

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71=21^x

71 = 2 1^{x}

x = \frac{ln ( 71 )}{ln ( 21 )}

Decimal Notation

x = 1.40011 \dots

Solution steps

71 = 2 1^{x}

Apply exponent rules

ln (71) = x ln (21)

Solve

ln (71) = x ln (21) : x = \frac{ln ( 71 )}{ln ( 21 )}

x = \frac{ln ( 71 )}{ln ( 21 )}

5^{2 x} = 5^{x} + 30

300 = 1500 - 1500 (0.9)^{t}

2 \cdot 7^{- 6 x} = 36

e^{2 x} - 1 = 0

a, e^{2 ab} = e^{a}