What are the solutions to the equation x^2-14=5x ?

The solutions to the equation x^2-14=5x are x=7,x=-2

Find the zeros of x^2-14=5x

The zeros of x^2-14=5x are x=7,x=-2

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x^{2} - 14 = 5 x

x = 7, x = - 2

Solution steps

x^{2} - 14 = 5 x

Move

5 x

to the left side

x^{2} - 14 - 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 5 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 14) = 9

x_{1, 2} = \frac{- ( - 5 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 9}{2 \cdot 1}

x = \frac{- ( - 5 ) + 9}{2 \cdot 1} : 7

x = \frac{- ( - 5 ) - 9}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 7, x = - 2

(\frac{32}{1024})^{\frac{1}{5}}

y^{2} - 17 y + 70 < 0

2 x^{2} + 288 = 0

\frac{2 + 3 i}{4 - 2 i}

3 (2 x - 7) = 3

What are the solutions to the equation x^2-14=5x ?
The solutions to the equation x^2-14=5x are x=7,x=-2
Find the zeros of x^2-14=5x
The zeros of x^2-14=5x are x=7,x=-2