What is the answer to solvefor q,p=7^{4-q} ?

The answer to solvefor q,p=7^{4-q} is q=-(ln(p)-4ln(7))/(ln(7))

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solvefor q,p=7^{4-q}

solve for

q, p = 7^{4 - q}

q = - \frac{ln ( p ) - 4 ln ( 7 )}{ln ( 7 )}

Solution steps

p = 7^{4 - q}

Apply exponent rules

ln (p) = (4 - q) ln (7)

Solve

ln (p) = (4 - q) ln (7) : q = - \frac{ln ( p ) - 4 ln ( 7 )}{ln ( 7 )}

q = - \frac{ln ( p ) - 4 ln ( 7 )}{ln ( 7 )}

x, y^{2} = 2^{x}

(0.25)^{(x - 3)} = 2^{(x + 8)}

y, 7^{2 y} = 3^{4}

2^{20 x + 10} = 3 2^{4 x + 2}

e^{2 l n (x)} = 196

What is the answer to solvefor q,p=7^{4-q} ?
The answer to solvefor q,p=7^{4-q} is q=-(ln(p)-4ln(7))/(ln(7))