What is the answer to 3^{n+1}*243=3^{-3n} ?

The answer to 3^{n+1}*243=3^{-3n} is n=-3/2

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3^{n+1}*243=3^{-3n}

3^{n + 1} \cdot 243 = 3^{- 3 n}

n = - \frac{3}{2}

Decimal Notation

n = - 1.5

Solution steps

3^{n + 1} \cdot 243 = 3^{- 3 n}

Apply exponent rules

n + 6 = - 3 n

Solve

n + 6 = - 3 n : n = - \frac{3}{2}

n = - \frac{3}{2}

g^{x - 1} - 2 = 25

e^{0.5 t} = 7

j (x) = 5 e^{- (x + 2)}

3^{3 x + 2} = 12

3^{3 x + 2} = 15

What is the answer to 3^{n+1}*243=3^{-3n} ?
The answer to 3^{n+1}*243=3^{-3n} is n=-3/2
Solve for n: 3^{n+1}*243=3^{-3n}
The solution is n=-3/2