3^{3x+2}=12

الحلّ

3^{3 x + 2} = 12

x = \frac{ln ( \frac{4}{3} )}{3 ln ( 3 )}

العشري

x = 0.08728 \dots

خطوات الحلّ

3^{3 x + 2} = 12

فعّل قانون القوى

(3 x + 2) ln (3) = ln (12)

(3 x + 2) ln (3) = ln (12)

حلّ:

x = \frac{ln ( \frac{4}{3} )}{3 ln ( 3 )}

x = \frac{ln ( \frac{4}{3} )}{3 ln ( 3 )}

3^{3 x + 2} = 15

3^{x} 0. 4^{2 x + 1} = 6^{x + 2}

12 = 10 e^{0.01 t}

2. 5^{3 x + 2} = 0. 4^{1 - 2 x}

4^{2 x - 3} + 1 6^{x - 1} = \frac{5}{64}