What is the answer to 3^x0.4^{2x+1}=6^{x+2} ?

The answer to 3^x0.4^{2x+1}=6^{x+2} is x=(log_{3}(90))/(1+log_{3)(2/75)}

Solve for x: 3^x0.4^{2x+1}=6^{x+2}

The solution is x=(log_{3}(90))/(1+log_{3)(2/75)}

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3^{x} 0. 4^{2 x + 1} = 6^{x + 2}

x = \frac{lo g _{3} ( 90 )}{1 + lo g _{3} ( \frac{2}{75} )}

Decimal Notation

x = - 1.78158 \dots

Solution steps

3^{x} \cdot 0. 4^{2 x + 1} = 6^{x + 2}

Apply exponent rules

x + lo g_{3} (\frac{2}{5}) (2 x + 1) = lo g_{3} (6) (x + 2)

Solve

x + lo g_{3} (\frac{2}{5}) (2 x + 1) = lo g_{3} (6) (x + 2) : x = \frac{lo g _{3} ( 90 )}{1 + lo g _{3} ( \frac{2}{75} )}

x = \frac{lo g _{3} ( 90 )}{1 + lo g _{3} ( \frac{2}{75} )}

12 = 10 e^{0.01 t}

2. 5^{3 x + 2} = 0. 4^{1 - 2 x}

4^{2 x - 3} + 1 6^{x - 1} = \frac{5}{64}

5^{2 x} - 26 (5^{x}) + 25 = 0

4^{x + 7} = 256

What is the answer to 3^x0.4^{2x+1}=6^{x+2} ?
The answer to 3^x0.4^{2x+1}=6^{x+2} is x=(log_{3}(90))/(1+log_{3)(2/75)}
Solve for x: 3^x0.4^{2x+1}=6^{x+2}
The solution is x=(log_{3}(90))/(1+log_{3)(2/75)}