What is the answer to 4^{2x-3}+16^{x-1}= 5/64 ?

The answer to 4^{2x-3}+16^{x-1}= 5/64 is x=0

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4^{2x-3}+16^{x-1}= 5/64

4^{2 x - 3} + 1 6^{x - 1} = \frac{5}{64}

x = 0

Solution steps

4^{2 x - 3} + 1 6^{x - 1} = \frac{5}{64}

Apply exponent rules

2 x ln (4) = ln (1)

Solve

2 x ln (4) = ln (1) : x = 0

x = 0

5^{2 x} - 26 (5^{x}) + 25 = 0

4^{x + 7} = 256

2 (3^{2 x}) + 3^{x} - 15 = 0

7^{3 x} = 4 9^{x + 3}

2 + 5 (3)^{7 x - 4} = 92

What is the answer to 4^{2x-3}+16^{x-1}= 5/64 ?
The answer to 4^{2x-3}+16^{x-1}= 5/64 is x=0
Solve for x: 4^{2x-3}+16^{x-1}= 5/64
The solution is x=0