What is the answer to 2+5(3)^{7x-4}=92 ?

The answer to 2+5(3)^{7x-4}=92 is x=(ln(1458))/(7ln(3))

Solve for x: 2+5(3)^{7x-4}=92

The solution is x=(ln(1458))/(7ln(3))

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2 + 5 (3)^{7 x - 4} = 92

x = \frac{ln ( 1458 )}{7 ln ( 3 )}

Decimal Notation

x = 0.94727 \dots

Solution steps

2 + 5 (3)^{7 x - 4} = 92

Move

2

to the right side

5 \cdot 3^{7 x - 4} = 90

Divide both sides by

5

3^{7 x - 4} = 18

Apply exponent rules

(7 x - 4) ln (3) = ln (18)

Solve

(7 x - 4) ln (3) = ln (18) : x = \frac{ln ( 1458 )}{7 ln ( 3 )}

x = \frac{ln ( 1458 )}{7 ln ( 3 )}

0.9 9^{x} = 0.5

3^{x - 9} = 2 7^{x^{2} - 3}

2^{(x^{2} - 4 x + 6)} = 8

7 e^{6 x} = 42

3^{(x + 1)} = 27

What is the answer to 2+5(3)^{7x-4}=92 ?
The answer to 2+5(3)^{7x-4}=92 is x=(ln(1458))/(7ln(3))
Solve for x: 2+5(3)^{7x-4}=92
The solution is x=(ln(1458))/(7ln(3))