What is the answer to 3^{x-9}=27^{x^2-3} ?

The answer to 3^{x-9}=27^{x^2-3} is x= 1/3 ,x=0

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3^{x-9}=27^{x^2-3}

3^{x - 9} = 2 7^{x^{2} - 3}

x = \frac{1}{3}, x = 0

Decimal Notation

x = 0.33333 \dots, x = 0

Solution steps

3^{x - 9} = 2 7^{x^{2} - 3}

Apply exponent rules

x - 9 = 3 (x^{2} - 3)

Solve

x - 9 = 3 (x^{2} - 3) : x = \frac{1}{3}, x = 0

x = \frac{1}{3}, x = 0

2^{(x^{2} - 4 x + 6)} = 8

7 e^{6 x} = 42

3^{(x + 1)} = 27

e^{2 x - 5} + 1 = 4

2^{2 x + 1} = 20

What is the answer to 3^{x-9}=27^{x^2-3} ?
The answer to 3^{x-9}=27^{x^2-3} is x= 1/3 ,x=0
Solve for x: 3^{x-9}=27^{x^2-3}
The solution is x= 1/3 ,x=0