What is the answer to 2^{2x+1}=20 ?

The answer to 2^{2x+1}=20 is x=(ln(10))/(2ln(2))

Solve for x: 2^{2x+1}=20

The solution is x=(ln(10))/(2ln(2))

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2^{2 x + 1} = 20

x = \frac{ln ( 10 )}{2 ln ( 2 )}

Decimal Notation

x = 1.66096 \dots

Solution steps

2^{2 x + 1} = 20

Apply exponent rules

(2 x + 1) ln (2) = ln (20)

Solve

(2 x + 1) ln (2) = ln (20) : x = \frac{ln ( 10 )}{2 ln ( 2 )}

x = \frac{ln ( 10 )}{2 ln ( 2 )}

8^{x + 1} = 32

5^{2 x - 1} = 25

7^{x + 4} = 1 0^{x}

1.0 7^{n} = 2

e^{(2 x - 1)} = 3

What is the answer to 2^{2x+1}=20 ?
The answer to 2^{2x+1}=20 is x=(ln(10))/(2ln(2))
Solve for x: 2^{2x+1}=20
The solution is x=(ln(10))/(2ln(2))