What is the answer to log_{10}(2^x)= 3/2 ?

The answer to log_{10}(2^x)= 3/2 is x=(3ln(10))/(2ln(2))

Solve for x: log_{10}(2^x)= 3/2

The solution is x=(3ln(10))/(2ln(2))

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lo g_{10} (2^{x}) = \frac{3}{2}

x = \frac{3 ln ( 10 )}{2 ln ( 2 )}

Decimal Notation

x = 4.98289 \dots

Solution steps

lo g_{10} (2^{x}) = \frac{3}{2}

Rewrite the equation with

2^{x} = u

lo g_{10} (u) = \frac{3}{2}

Solve

lo g_{10} (u) = \frac{3}{2} : u = 1010

u = 1010

Substitute back

u = 2^{x},

solve for

x

Solve

2^{x} = 1010 : x = \frac{3 ln ( 10 )}{2 ln ( 2 )}

x = \frac{3 ln ( 10 )}{2 ln ( 2 )}

5^{x^{2}} = 2 5^{x}

2^{x} = \frac{4 ^{7}}{8 ^{3}}

(\frac{1}{8})^{2 - 3 x} = 3 2^{4 + x}

2^{2 x - 7} - 9 \cdot 2^{x - 1} + 256 = 0

x, 3 e^{x} = 5 + 8 e^{- x}

What is the answer to log_{10}(2^x)= 3/2 ?
The answer to log_{10}(2^x)= 3/2 is x=(3ln(10))/(2ln(2))
Solve for x: log_{10}(2^x)= 3/2
The solution is x=(3ln(10))/(2ln(2))