What is the answer to (1/8)^{2-3x}=32^{4+x} ?

The answer to (1/8)^{2-3x}=32^{4+x} is x= 13/2

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(1/8)^{2-3x}=32^{4+x}

(\frac{1}{8})^{2 - 3 x} = 3 2^{4 + x}

x = \frac{13}{2}

Decimal Notation

x = 6.5

Solution steps

(\frac{1}{8})^{2 - 3 x} = 3 2^{4 + x}

Apply exponent rules

- 3 (2 - 3 x) = 5 (4 + x)

Solve

- 3 (2 - 3 x) = 5 (4 + x) : x = \frac{13}{2}

x = \frac{13}{2}

2^{2 x - 7} - 9 \cdot 2^{x - 1} + 256 = 0

x, 3 e^{x} = 5 + 8 e^{- x}

4^{2 x + 1} = 0. 5^{3 x + 2}

9^{x + 1} = 2 7^{2 x - 5}

What is the answer to (1/8)^{2-3x}=32^{4+x} ?
The answer to (1/8)^{2-3x}=32^{4+x} is x= 13/2
Solve for x: (1/8)^{2-3x}=32^{4+x}
The solution is x= 13/2