What is the answer to 9^{x+1}=27^{2x-5} ?

The answer to 9^{x+1}=27^{2x-5} is x= 17/4

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9^{x+1}=27^{2x-5}

9^{x + 1} = 2 7^{2 x - 5}

x = \frac{17}{4}

Decimal Notation

x = 4.25

Solution steps

9^{x + 1} = 2 7^{2 x - 5}

Apply exponent rules

2 (x + 1) = 3 (2 x - 5)

Solve

2 (x + 1) = 3 (2 x - 5) : x = \frac{17}{4}

x = \frac{17}{4}

x, e^{x y} = 2

3^{x + 4} + 3^{x + 2} + 3^{x} = 273

4^{x} + 2^{x + 1} = 8

64 = 3 2^{x - 3}

2^{x + 1} + 2^{x} = \frac{3}{2}

What is the answer to 9^{x+1}=27^{2x-5} ?
The answer to 9^{x+1}=27^{2x-5} is x= 17/4
Solve for x: 9^{x+1}=27^{2x-5}
The solution is x= 17/4