What is the answer to 3^{x+4}+3^{x+2}+3^x=273 ?

The answer to 3^{x+4}+3^{x+2}+3^x=273 is x=1

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3^{x+4}+3^{x+2}+3^x=273

3^{x + 4} + 3^{x + 2} + 3^{x} = 273

x = 1

Solution steps

3^{x + 4} + 3^{x + 2} + 3^{x} = 273

Factor

3^{x + 4} + 3^{x + 2} + 3^{x} : 91 \cdot 3^{x}

91 \cdot 3^{x} = 273

Divide both sides by

91

3^{x} = 3

Apply exponent rules

x = 1

4^{x} + 2^{x + 1} = 8

64 = 3 2^{x - 3}

2^{x + 1} + 2^{x} = \frac{3}{2}

2^{(x + 1)} + 2^{(x - 1)} = 20

x, 7^{2 x + y x} = k

What is the answer to 3^{x+4}+3^{x+2}+3^x=273 ?
The answer to 3^{x+4}+3^{x+2}+3^x=273 is x=1
Solve for x: 3^{x+4}+3^{x+2}+3^x=273
The solution is x=1