What are the solutions to the equation x^2-16x=-40 ?

The solutions to the equation x^2-16x=-40 are x=2(4+sqrt(6)),x=2(4-sqrt(6))

Find the zeros of x^2-16x=-40

The zeros of x^2-16x=-40 are x=2(4+sqrt(6)),x=2(4-sqrt(6))

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x^{2} - 16 x = - 40

x = 2 (4 + 6), x = 2 (4 - 6)

Solution steps

x^{2} - 16 x = - 40

Move

40

to the left side

x^{2} - 16 x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 40 = 46

x_{1, 2} = \frac{- ( - 16 ) \pm 4 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 6}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 4 6}{2 \cdot 1}

x = \frac{- ( - 16 ) + 4 6}{2 \cdot 1} : 2 (4 + 6)

x = \frac{- ( - 16 ) - 4 6}{2 \cdot 1} : 2 (4 - 6)

The solutions to the quadratic equation are:

x = 2 (4 + 6), x = 2 (4 - 6)

7 x^{2} - 7 x - 294

v^{2} + 8 v + 15 = 0

t + 2 < 13

e^{x} = 0

6 x^{2} + 12 x = - 2

What are the solutions to the equation x^2-16x=-40 ?
The solutions to the equation x^2-16x=-40 are x=2(4+sqrt(6)),x=2(4-sqrt(6))
Find the zeros of x^2-16x=-40
The zeros of x^2-16x=-40 are x=2(4+sqrt(6)),x=2(4-sqrt(6))