What is the answer to solvefor y,x=sqrt(3-e^{2y)} ?

The answer to solvefor y,x=sqrt(3-e^{2y)} is y=(ln(3-x^2))/2

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solvefor y,x=sqrt(3-e^{2y)}

solve for

y, x = 3 - e^{2 y}

y = \frac{ln ( 3 - x ^{2} )}{2}

Solution steps

x = 3 - e^{2 y}

Rewrite the equation with

e^{2 y} = u

x = 3 - u

Solve

x = 3 - u : u = 3 - x^{2} {x \geq 0}

u = 3 - x^{2} {x \geq 0}

Substitute back

u = e^{2 y},

solve for

y

Solve

e^{2 y} = 3 - x^{2} : y = \frac{ln ( 3 - x ^{2} )}{2}

y = \frac{ln ( 3 - x ^{2} )}{2}

1 6^{x} = \frac{1}{4}

x, z = ln (e^{x} + e^{y})

e^{l n (x)} = 0

2^{x + 1} - 2^{x - 3} + 2^{x} = 23

4^{x} + 2^{x + 3} = 48

What is the answer to solvefor y,x=sqrt(3-e^{2y)} ?
The answer to solvefor y,x=sqrt(3-e^{2y)} is y=(ln(3-x^2))/2