What is the answer to 8(4^{6-2x})+13=41 ?

The answer to 8(4^{6-2x})+13=41 is x=(ln(8192/7))/(4ln(2))

Solve for x: 8(4^{6-2x})+13=41

The solution is x=(ln(8192/7))/(4ln(2))

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8 (4^{6 - 2 x}) + 13 = 41

x = \frac{ln ( \frac{8192}{7} )}{4 ln ( 2 )}

Decimal Notation

x = 2.54816 \dots

Solution steps

8 (4^{6 - 2 x}) + 13 = 41

Move

13

to the right side

8 \cdot 4^{6 - 2 x} = 28

Divide both sides by

8

4^{6 - 2 x} = \frac{7}{2}

Apply exponent rules

(6 - 2 x) ln (4) = ln (\frac{7}{2})

Solve

(6 - 2 x) ln (4) = ln (\frac{7}{2}) : x = \frac{ln ( \frac{8192}{7} )}{4 ln ( 2 )}

x = \frac{ln ( \frac{8192}{7} )}{4 ln ( 2 )}

7^{x} = 2 \cdot 5^{x}

6^{x} = \frac{1}{6}

200 = \frac{500}{1 + e ^{3 - t}}

5^{2 x} + 5^{1 + x} - 6 = 0

4^{5 - 2 x} = 3^{x}

What is the answer to 8(4^{6-2x})+13=41 ?
The answer to 8(4^{6-2x})+13=41 is x=(ln(8192/7))/(4ln(2))
Solve for x: 8(4^{6-2x})+13=41
The solution is x=(ln(8192/7))/(4ln(2))