What is the answer to 3^{2x^2+3x-2}=1 ?

The answer to 3^{2x^2+3x-2}=1 is x= 1/2 ,x=-2

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3^{2x^2+3x-2}=1

3^{2 x^{2} + 3 x - 2} = 1

x = \frac{1}{2}, x = - 2

Decimal Notation

x = 0.5, x = - 2

Solution steps

3^{2 x^{2} + 3 x - 2} = 1

Apply exponent rules

(2 x^{2} + 3 x - 2) ln (3) = ln (1)

Solve

(2 x^{2} + 3 x - 2) ln (3) = ln (1) : x = \frac{1}{2}, x = - 2

x = \frac{1}{2}, x = - 2

8 1^{x^{2} - 1} = 2 7^{- (7 - 5 x)}

6 (4^{x}) - 11 (2^{x}) + 4 = 0

6300 = 3130 \cdot 1.0 8^{x}

2^{r} = (\frac{1}{3})^{r - 1}

10 = 2^{\frac{t}{3}}

What is the answer to 3^{2x^2+3x-2}=1 ?
The answer to 3^{2x^2+3x-2}=1 is x= 1/2 ,x=-2
Solve for x: 3^{2x^2+3x-2}=1
The solution is x= 1/2 ,x=-2