What is the answer to 3^{2x-3}=6 ?

The answer to 3^{2x-3}=6 is x=(ln(162))/(2ln(3))

Solve for x: 3^{2x-3}=6

The solution is x=(ln(162))/(2ln(3))

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3^{2 x - 3} = 6

x = \frac{ln ( 162 )}{2 ln ( 3 )}

Decimal Notation

x = 2.31546 \dots

Solution steps

3^{2 x - 3} = 6

Apply exponent rules

(2 x - 3) ln (3) = ln (6)

Solve

(2 x - 3) ln (3) = ln (6) : x = \frac{ln ( 162 )}{2 ln ( 3 )}

x = \frac{ln ( 162 )}{2 ln ( 3 )}

2^{x - 3} = 5

9 (5^{x}) = 8^{x + 4}

5^{6 x + 1} - 6 \cdot 5^{3 x} + 1 = 0

(2)^{x} = 16

3^{x} - 3^{1 - x} = 2

What is the answer to 3^{2x-3}=6 ?
The answer to 3^{2x-3}=6 is x=(ln(162))/(2ln(3))
Solve for x: 3^{2x-3}=6
The solution is x=(ln(162))/(2ln(3))