What is the answer to (3^x)/(9^{2x+3)}=1 ?

The answer to (3^x)/(9^{2x+3)}=1 is x=-2

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(3^x)/(9^{2x+3)}=1

\frac{3 ^{x}}{9 ^{2 x + 3}} = 1

x = - 2

Solution steps

\frac{3 ^{x}}{9 ^{2 x + 3}} = 1

Apply exponent rules

(x + 2 (- 2 x - 3)) ln (3) = ln (1)

Solve

(x + 2 (- 2 x - 3)) ln (3) = ln (1) : x = - 2

x = - 2

Verify Solutions:

x = - 2

True

The solution is

x = - 2

6^{x} = 6

6 4^{x^{2}} = 1 6^{x^{2} + 2 x}

\frac{5 ^{2 - x}}{5 ^{x}} = 5^{16}

2^{4 x - x^{2}} = 8

\frac{2 ^{x - 3}}{4 ^{10}} = 8^{3}

What is the answer to (3^x)/(9^{2x+3)}=1 ?
The answer to (3^x)/(9^{2x+3)}=1 is x=-2
Solve for x: (3^x)/(9^{2x+3)}=1
The solution is x=-2