What is the answer to 2^{2x^2-2}-8^x=0 ?

The answer to 2^{2x^2-2}-8^x=0 is x=2,x=-1/2

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2^{2x^2-2}-8^x=0

2^{2 x^{2} - 2} - 8^{x} = 0

x = 2, x = - \frac{1}{2}

Solution steps

2^{2 x^{2} - 2} - 8^{x} = 0

Add

8^{x}

to both sides

2^{2 x^{2} - 2} - 8^{x} + 8^{x} = 0 + 8^{x}

Simplify

2^{2 x^{2} - 2} = 8^{x}

Apply exponent rules

2 x^{2} - 2 = 3 x

Solve

2 x^{2} - 2 = 3 x : x = 2, x = - \frac{1}{2}

x = 2, x = - \frac{1}{2}

4^{x - 1} = 7

4^{x - 1} = 1

9^{x + 1} = 27

3^{2 x + 5} = 2 7^{x - 1}

72 9^{x - 5} = (3^{2})^{1 - x}

What is the answer to 2^{2x^2-2}-8^x=0 ?
The answer to 2^{2x^2-2}-8^x=0 is x=2,x=-1/2
Solve for x: 2^{2x^2-2}-8^x=0
The solution is x=2,x=-1/2