What is the answer to 2^{y+1}=5 ?

The answer to 2^{y+1}=5 is y=(ln(5))/(ln(2))-1

Solve for y: 2^{y+1}=5

The solution is y=(ln(5))/(ln(2))-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{y + 1} = 5

y = \frac{ln ( 5 )}{ln ( 2 )} - 1

Solution steps

2^{y + 1} = 5

Apply exponent rules

(y + 1) ln (2) = ln (5)

Solve

(y + 1) ln (2) = ln (5) : y = \frac{ln ( 5 )}{ln ( 2 )} - 1

y = \frac{ln ( 5 )}{ln ( 2 )} - 1

69 = 1 1^{x}

2^{2 x} = 5^{1 - 2 x}

2 \cdot 3^{x} = 5^{2 x}

3^{x} + 3^{x - 1} = 4

\frac{( e ^{x} )}{1 - x} = 0

What is the answer to 2^{y+1}=5 ?
The answer to 2^{y+1}=5 is y=(ln(5))/(ln(2))-1
Solve for y: 2^{y+1}=5
The solution is y=(ln(5))/(ln(2))-1