What is the answer to 3^{2x-1}=8^x ?

The answer to 3^{2x-1}=8^x is x=(ln(3))/(2ln(3)-3ln(2))

Solve for x: 3^{2x-1}=8^x

The solution is x=(ln(3))/(2ln(3)-3ln(2))

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3^{2 x - 1} = 8^{x}

x = \frac{ln ( 3 )}{2 ln ( 3 ) - 3 ln ( 2 )}

Solution steps

3^{2 x - 1} = 8^{x}

Apply exponent rules

(2 x - 1) ln (3) = x ln (8)

Solve

(2 x - 1) ln (3) = x ln (8) : x = \frac{ln ( 3 )}{2 ln ( 3 ) - 3 ln ( 2 )}

x = \frac{ln ( 3 )}{2 ln ( 3 ) - 3 ln ( 2 )}

\frac{2 7 ^{- 4} 9}{8 1 ^{- 2}} = 3^{x}

2 5^{x} = 625

\frac{1}{3} 3^{4 x + 2} - 3^{2 x - 5} = 0

9^{x + 1} - 3^{x + 3} - 3^{x} + 3 = 0

What is the answer to 3^{2x-1}=8^x ?
The answer to 3^{2x-1}=8^x is x=(ln(3))/(2ln(3)-3ln(2))
Solve for x: 3^{2x-1}=8^x
The solution is x=(ln(3))/(2ln(3)-3ln(2))