What is the answer to solvefor n,p= 1/(10^n) ?

The answer to solvefor n,p= 1/(10^n) is n=-(ln(p))/(ln(10))

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solvefor n,p= 1/(10^n)

solve for

n, p = \frac{1}{1 0 ^{n}}

n = - \frac{ln ( p )}{ln ( 10 )}

Solution steps

p = \frac{1}{1 0 ^{n}}

Apply exponent rules

ln (p) = - n ln (10)

Solve

ln (p) = - n ln (10) : n = - \frac{ln ( p )}{ln ( 10 )}

n = - \frac{ln ( p )}{ln ( 10 )}

Verify Solutions:

n = - \frac{ln ( p )}{ln ( 10 )}

True

The solution is

n = - \frac{ln ( p )}{ln ( 10 )}

2^{2 x + 18} = 3^{x - 12}

e^{x} = 17.8

x e^{x} - e^{x} = 0

6 = e^{x}

m, 9^{m} = 3^{n}

What is the answer to solvefor n,p= 1/(10^n) ?
The answer to solvefor n,p= 1/(10^n) is n=-(ln(p))/(ln(10))