What is the answer to 2^{3x-1}=6 ?

The answer to 2^{3x-1}=6 is x=(ln(12))/(3ln(2))

Solve for x: 2^{3x-1}=6

The solution is x=(ln(12))/(3ln(2))

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2^{3 x - 1} = 6

x = \frac{ln ( 12 )}{3 ln ( 2 )}

Solution steps

2^{3 x - 1} = 6

Apply exponent rules

(3 x - 1) ln (2) = ln (6)

Solve

(3 x - 1) ln (2) = ln (6) : x = \frac{ln ( 12 )}{3 ln ( 2 )}

x = \frac{ln ( 12 )}{3 ln ( 2 )}

e^{x} - 4 = 10

9^{x} + 2 (3^{x}) = 3^{x + 2} - 12

1000000 = 2^{n}

3^{3 x} + 3 = 6561

2^{2 x + 1} + 4^{x - 1} = 9

What is the answer to 2^{3x-1}=6 ?
The answer to 2^{3x-1}=6 is x=(ln(12))/(3ln(2))
Solve for x: 2^{3x-1}=6
The solution is x=(ln(12))/(3ln(2))