What is the answer to \sqrt[4]{3^x}=\sqrt[3]{9} ?

The answer to \sqrt[4]{3^x}=\sqrt[3]{9} is x= 8/3

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\sqrt[4]{3^x}=\sqrt[3]{9}

x = \frac{8}{3}

Decimal Notation

x = 2.66666 \dots

Solution steps

Apply exponent rules

x \frac{1}{4} = \frac{2}{3}

Solve

x \frac{1}{4} = \frac{2}{3} : x = \frac{8}{3}

x = \frac{8}{3}

(x + 2)^{x + 4} = (x + 2)^{x^{2} + 3 x + 1}

25.4 = 2.2 1^{x^{365}}

2^{x} = x + 2

15 \cdot 5^{x} = 53 \cdot 2^{x}

5^{x} = 120

What is the answer to \sqrt[4]{3^x}=\sqrt[3]{9} ?
The answer to \sqrt[4]{3^x}=\sqrt[3]{9} is x= 8/3
Solve for x: \sqrt[4]{3^x}=\sqrt[3]{9}
The solution is x= 8/3