What is the answer to 15*5^x=53*2^x ?

The answer to 15*5^x=53*2^x is x=(ln(53)-ln(15))/(ln(5)-ln(2))

Solve for x: 15*5^x=53*2^x

The solution is x=(ln(53)-ln(15))/(ln(5)-ln(2))

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15 \cdot 5^{x} = 53 \cdot 2^{x}

x = \frac{ln ( 53 ) - ln ( 15 )}{ln ( 5 ) - ln ( 2 )}

Decimal Notation

x = 1.37755 \dots

Solution steps

15 \cdot 5^{x} = 53 \cdot 2^{x}

Apply exponent rules

ln (15) + x ln (5) = ln (53) + x ln (2)

Solve

ln (15) + x ln (5) = ln (53) + x ln (2) : x = \frac{ln ( 53 ) - ln ( 15 )}{ln ( 5 ) - ln ( 2 )}

x = \frac{ln ( 53 ) - ln ( 15 )}{ln ( 5 ) - ln ( 2 )}

5^{x} = 120

x, y = e^{- 2 x}

2^{x + 7} \cdot 4^{x - 1} = 8^{2 x + 3}

3000 = 100 e^{n}

6^{2 x - 7} = 216

What is the answer to 15*5^x=53*2^x ?
The answer to 15*5^x=53*2^x is x=(ln(53)-ln(15))/(ln(5)-ln(2))
Solve for x: 15*5^x=53*2^x
The solution is x=(ln(53)-ln(15))/(ln(5)-ln(2))