What is the answer to 4^{x^2}*2^{7x}=16 ?

The answer to 4^{x^2}*2^{7x}=16 is x= 1/2 ,x=-4

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4^{x^2}*2^{7x}=16

4^{x^{2}} \cdot 2^{7 x} = 16

x = \frac{1}{2}, x = - 4

Decimal Notation

x = 0.5, x = - 4

Solution steps

4^{x^{2}} \cdot 2^{7 x} = 16

Apply exponent rules

2 x^{2} + 7 x = 4

Solve

2 x^{2} + 7 x = 4 : x = \frac{1}{2}, x = - 4

x = \frac{1}{2}, x = - 4

4^{x + 1} + 2^{x - 2} = 68

- e^{x + 1} = 2 x + 1

5^{x} = 5^{2 x + 1}

1 0^{- 2 x} = \frac{1}{10000}

5^{x^{2}} = (\frac{1}{25})^{x + 3}

What is the answer to 4^{x^2}*2^{7x}=16 ?
The answer to 4^{x^2}*2^{7x}=16 is x= 1/2 ,x=-4
Solve for x: 4^{x^2}*2^{7x}=16
The solution is x= 1/2 ,x=-4