What is the answer to 3*2^x=1 ?

The answer to 3*2^x=1 is x=-(ln(3))/(ln(2))

The solution is x=-(ln(3))/(ln(2))

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3*2^x=1

3 \cdot 2^{x} = 1

x = - \frac{ln ( 3 )}{ln ( 2 )}

Decimal Notation

x = - 1.58496 \dots

Solution steps

3 \cdot 2^{x} = 1

Divide both sides by

3

2^{x} = \frac{1}{3}

Apply exponent rules

x ln (2) = ln (\frac{1}{3})

Solve

x ln (2) = ln (\frac{1}{3}) : x = - \frac{ln ( 3 )}{ln ( 2 )}

x = - \frac{ln ( 3 )}{ln ( 2 )}

3^{x + 4} = 243

21 6^{x} = 6^{x + 10}

2^{2 x + 1} = 3 2^{x}

1 9^{x} = 143

2^{2 x - 1} = 3^{3 x + 4}