What is the answer to solvefor t,e^{t^2}=4 ?

The answer to solvefor t,e^{t^2}=4 is t=sqrt(2)sqrt(ln(2)),t=-sqrt(2)sqrt(ln(2))

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solvefor t,e^{t^2}=4

solve for

t, e^{t^{2}} = 4

t = 2 ln (2), t = - 2 ln (2)

Decimal Notation

t = 1.17741 \dots, t = - 1.17741 \dots

Solution steps

e^{t^{2}} = 4

Apply exponent rules

t^{2} = ln (4)

Solve

t^{2} = ln (4) : t = 2 ln (2), t = - 2 ln (2)

t = 2 ln (2), t = - 2 ln (2)

5^{x + 2} = 5^{2 x - 1}

\frac{2 ^{3 x - 1}}{2 ^{x + 5}} = 2^{x}

2^{x + 14} = 1 6^{2 x}

8^{- 4} = 4^{- 2 x - 4}

e^{- x} = - \frac{2}{( x + 1 )}

What is the answer to solvefor t,e^{t^2}=4 ?
The answer to solvefor t,e^{t^2}=4 is t=sqrt(2)sqrt(ln(2)),t=-sqrt(2)sqrt(ln(2))