What is the answer to 3^x=7^{x-3} ?

The answer to 3^x=7^{x-3} is x=(3ln(7))/(ln(7)-ln(3))

Solve for x: 3^x=7^{x-3}

The solution is x=(3ln(7))/(ln(7)-ln(3))

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3^{x} = 7^{x - 3}

x = \frac{3 ln ( 7 )}{ln ( 7 ) - ln ( 3 )}

Decimal Notation

x = 6.88982 \dots

Solution steps

3^{x} = 7^{x - 3}

Apply exponent rules

x ln (3) = (x - 3) ln (7)

Solve

x ln (3) = (x - 3) ln (7) : x = \frac{3 ln ( 7 )}{ln ( 7 ) - ln ( 3 )}

x = \frac{3 ln ( 7 )}{ln ( 7 ) - ln ( 3 )}

6^{3 t - 1} = 3 6^{t - 3}

ln (5) = e^{x}

4^{3 - 2 x} = 12

5^{x + 2} = 4

4^{4 x - 1} = \frac{1}{2}

What is the answer to 3^x=7^{x-3} ?
The answer to 3^x=7^{x-3} is x=(3ln(7))/(ln(7)-ln(3))
Solve for x: 3^x=7^{x-3}
The solution is x=(3ln(7))/(ln(7)-ln(3))