What is the answer to solvefor x,-e^{-y}=e^x+c ?

The answer to solvefor x,-e^{-y}=e^x+c is x=ln(-e^{-y}-c)

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solvefor x,-e^{-y}=e^x+c

solve for

x, - e^{- y} = e^{x} + c

x = ln (- e^{- y} - c)

Solution steps

- e^{- y} = e^{x} + c

Switch sides

e^{x} + c = - e^{- y}

Move

c

to the right side

e^{x} = - e^{- y} - c

Apply exponent rules

x = ln (- e^{- y} - c)

1 0^{2 x + 3} = 5

2^{n - 6} = 8^{2 - n}

2^{2 x} - 3 \cdot 2^{x + 1} + 8 = 0

4^{x - x^{2}} = \frac{1}{2}

4^{x} + 6^{x} - 2 \cdot 9^{x} = 0

What is the answer to solvefor x,-e^{-y}=e^x+c ?
The answer to solvefor x,-e^{-y}=e^x+c is x=ln(-e^{-y}-c)