What is the answer to 2^{3+5x}=4x-1 ?

The answer to 2^{3+5x}=4x-1 is No Solution for x\in\mathbb{R}

Solve for x: 2^{3+5x}=4x-1

The solution is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{3 + 5 x} = 4 x - 1

No Solution for x \in R

Solution steps

2^{3 + 5 x} = 4 x - 1

Prepare

2^{3 + 5 x} = 4 x - 1

for Lambert form:

1 = (4 x - 1) e^{l n (2) (- 3 - 5 x)}

Rewrite the equation with

(- 5 x + \frac{5}{4}) ln (2) = u

and

x = - \frac{4 u - 5 ln ( 2 )}{20 ln ( 2 )}

1 = (4 (- \frac{4 u - 5 ln ( 2 )}{20 ln ( 2 )}) - 1) e^{l n (2) (- 3 - 5 (- \frac{4 u - 5 l n ( 2 )}{20 l n ( 2 )}))}

Simplify

1 = e^{- 3 l n (2) + \frac{4 u - 5 l n ( 2 )}{4}} (- \frac{4 u - 5 ln ( 2 )}{5 ln ( 2 )} - 1)

Rewrite

1 = e^{- 3 l n (2) + \frac{4 u - 5 l n ( 2 )}{4}} (- \frac{4 u - 5 ln ( 2 )}{5 ln ( 2 )} - 1)

in Lambert form:

e^{u} u = - \frac{5 e ^{\frac{17 l n ( 2 )}{4}} ln ( 2 )}{4}

Solve

e^{u} u = - \frac{5 e ^{\frac{17 l n ( 2 )}{4}} ln ( 2 )}{4} :

No Solution for

u \in R

No Solution for x \in R

n, 2^{n} = 60000000

9^{2 x} = 2 7^{x^{2} - 5}

4^{x} + 1 + 4^{x} - 1 = 64

8 1^{p} = 1

5^{2 x} - 30 \cdot 5^{x} + 125 = 0

What is the answer to 2^{3+5x}=4x-1 ?
The answer to 2^{3+5x}=4x-1 is No Solution for x\in\mathbb{R}
Solve for x: 2^{3+5x}=4x-1
The solution is No Solution for x\in\mathbb{R}