What are the solutions to the equation 2(x+5)-x^2-5x=0 ?

The solutions to the equation 2(x+5)-x^2-5x=0 are x=-5,x=2

Find the zeros of 2(x+5)-x^2-5x=0

The zeros of 2(x+5)-x^2-5x=0 are x=-5,x=2

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2 (x + 5) - x^{2} - 5 x = 0

x = - 5, x = 2

Solution steps

2 (x + 5) - x^{2} - 5 x = 0

Expand

2 (x + 5) - x^{2} - 5 x : - x^{2} - 3 x + 10

- x^{2} - 3 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 1 ) \cdot 10}{2 ( - 1 )}

(- 3)^{2} - 4 (- 1) \cdot 10 = 7

x_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 7}{2 ( - 1 )}, x_{2} = \frac{- ( - 3 ) - 7}{2 ( - 1 )}

x = \frac{- ( - 3 ) + 7}{2 ( - 1 )} : - 5

x = \frac{- ( - 3 ) - 7}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = - 5, x = 2

\frac{( 2 a ^{- 1} ) ^{2}}{( 2 a ^{- 1} ) ^{- 2}}

61

2 x - 3 = 15

2 x^{2} + x + 2 = 0

3 x^{2} + x = 4

What are the solutions to the equation 2(x+5)-x^2-5x=0 ?
The solutions to the equation 2(x+5)-x^2-5x=0 are x=-5,x=2
Find the zeros of 2(x+5)-x^2-5x=0
The zeros of 2(x+5)-x^2-5x=0 are x=-5,x=2