What are the solutions to the equation 3x^2+x=4 ?

The solutions to the equation 3x^2+x=4 are x=1,x=-4/3

Find the zeros of 3x^2+x=4

The zeros of 3x^2+x=4 are x=1,x=-4/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + x = 4

x = 1, x = - \frac{4}{3}

Decimal Notation

x = 1, x = - 1.33333 \dots

Solution steps

3 x^{2} + x = 4

Move

4

to the left side

3 x^{2} + x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 4) = 7

x_{1, 2} = \frac{- 1 \pm 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 1 + 7}{2 \cdot 3}, x_{2} = \frac{- 1 - 7}{2 \cdot 3}

x = \frac{- 1 + 7}{2 \cdot 3} : 1

x = \frac{- 1 - 7}{2 \cdot 3} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{4}{3}

\frac{30 ab}{35 b c}

lo g_{5} (a^{7} b)

3.5 + 4.5

- 3 + 10

(\frac{2 x ^{3} y ^{2}}{- x ^{2} y ^{5}})^{- 2}

What are the solutions to the equation 3x^2+x=4 ?
The solutions to the equation 3x^2+x=4 are x=1,x=-4/3
Find the zeros of 3x^2+x=4
The zeros of 3x^2+x=4 are x=1,x=-4/3