What is the answer to (3^{x+1})(4^{x+2})=(5^{x+3}) ?

The answer to (3^{x+1})(4^{x+2})=(5^{x+3}) is x=(3ln(5)-ln(48))/(ln(12)-ln(5))

Solve for x: (3^{x+1})(4^{x+2})=(5^{x+3})

The solution is x=(3ln(5)-ln(48))/(ln(12)-ln(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(3^{x + 1}) (4^{x + 2}) = (5^{x + 3})

x = \frac{3 ln ( 5 ) - ln ( 48 )}{ln ( 12 ) - ln ( 5 )}

Decimal Notation

x = 1.09325 \dots

Solution steps

(3^{x + 1}) (4^{x + 2}) = (5^{x + 3})

Apply exponent rules

(x + 1) ln (12) + ln (4^{1}) = (x + 3) ln (5)

Solve

(x + 1) ln (12) + ln (4^{1}) = (x + 3) ln (5) : x = \frac{3 ln ( 5 ) - ln ( 48 )}{ln ( 12 ) - ln ( 5 )}

x = \frac{3 ln ( 5 ) - ln ( 48 )}{ln ( 12 ) - ln ( 5 )}

8^{x + 4} = 16

x^{2 x} = 16

4^{x + 2} \cdot 8^{3 x + 1} = 64

1 0^{x} = 45

1 0^{x} = 41

What is the answer to (3^{x+1})(4^{x+2})=(5^{x+3}) ?
The answer to (3^{x+1})(4^{x+2})=(5^{x+3}) is x=(3ln(5)-ln(48))/(ln(12)-ln(5))
Solve for x: (3^{x+1})(4^{x+2})=(5^{x+3})
The solution is x=(3ln(5)-ln(48))/(ln(12)-ln(5))